Challenge #1 of 1

Suppose we have the following class:

class DinosaurHatcher
{
    public function __construct(private LoggerInterface $logger)
    {
    }

    public function getProgressTowardsHatching(): int
    {
        // ...
    }

    public function warmEgg(): void
    {
        // ...
    }
}

In a test for a different class, we decide to mock this:

$hatcher = $this->createMock(DinosaurHatcher::class);

What will happen if we call $hatcher->getProgressTowardsHatching() or $hatcher->warmEgg()?

Trick question! This will trigger an error: you can't mock a class that has required constructor arguments!

Nothing will happen when you call those methods: the "normal" logic will not be executed. If you look at the return values of the methods, both will return null.

Since we haven't controlled the return value yet with $hatcher->willReturn(), both methods will run their normal logic and return the normal value.

Nothing will happen when you call those methods: the "normal" logic will not be executed. If you look at the return values of the methods, warmEgg() will return null and getProgressTowardsHatching() will return 0.

Rewatch Video

TRACK

Testing >

COURSE

PHPUnit: Unit Testing with a Bite! >

CHAPTER

Mocking: Test Doubles

Challenge #1 of 1